Election in Tennessee
1832 United States presidential election in Tennessee ← 1828 | November 2 – December 5, 1832 | 1836 → |
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| | | Nominee | Andrew Jackson | Henry Clay | | Party | Democratic | National Republican | Home state | Tennessee | Kentucky | Running mate | Martin Van Buren | John Sergeant | Electoral vote | 15 | 0 | Popular vote | 28,078 | 1,347 | Percentage | 95.42% | 4.58% | |
Precinct before election Andrew Jackson Democratic | Elected Precinct Andrew Jackson Democratic | |
Elections in Tennessee |
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Government |
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The 1832 United States presidential election in Tennessee took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
Tennessee voted for the Democratic Party candidate, state native Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Tennessee by a large margin of 90.84 percent. This is the most recent election in which Blount County, Carter County, Cocke County, Grainger County, Jefferson County, and Sevier County voted for a Democratic presidential candidate.
Results
References
- ^ "1832 Presidential General Election Results — Tennessee". U.S. Election Atlas. Retrieved April 12, 2013.
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