Election in Louisiana
1832 United States presidential election in Louisiana
|
← 1828 | November 2 – December 5, 1832 | 1836 → |
|
| | | Nominee | Andrew Jackson | Henry Clay | | Party | Democratic | National Republican | Home state | Tennessee | Kentucky | Running mate | Martin Van Buren | John Sergeant | Electoral vote | 5 | 0 | Popular vote | 3,908 | 2,429 | Percentage | 61.67% | 38.33% | |
President before election Andrew Jackson Democratic | Elected President Andrew Jackson Democratic | |
Elections in Louisiana |
---|
|
|
|
|
|
|
|
Government |
|
The 1832 United States presidential election in Louisiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Louisiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Louisiana by a margin of 23.34%.
Results
See also
References
- ^ "1832 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved April 12, 2013.
|
---|
President | |
---|
U.S. Senate | |
---|
U.S. House | |
---|
Governors | |
---|
Mayors | |
---|
States and territories | - Alabama
- Connecticut
- Delaware
- Georgia
- Illinois
- Indiana
- Kentucky
- Louisiana
- Maine
- Maryland
- Massachusetts
- Mississippi
- Missouri
- New Hampshire
- New Jersey
- New York
- North Carolina
- Ohio
- Pennsylvania
- Rhode Island
- South Carolina
- Tennessee
- Vermont
- Virginia
|
---|