1844 United States presidential election in Ohio
Election in Ohio
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The 1844 United States presidential election in Ohio took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Ohio by a narrow margin of 1.94%.
Results
| 1844 United States presidential election in Ohio[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 155,113 | 49.68% | 23 | 100.00% | ||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 149,061 | 47.74% | 0 | 0.00% | ||
| Liberty | James G. Birney of Michigan | Thomas Morris of Ohio | 8,050 | 2.58% | 0 | 0.00% | ||
| Total | 312,224 | 100.00% | 23 | 100.00% | ||||
See also
References
- ^ "1844 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved December 23, 2013.
State and district results of the 1844 United States presidential election | ||
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