Election in Connecticut
1836 United States presidential election in Connecticut
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| ← 1832 | November 3 – December 7, 1836 | 1840 → |
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| |  |  | | Nominee | Martin Van Buren | William Henry Harrison | | | Party | Democratic | Whig | | Home state | New York | Ohio | | Running mate | Richard Johnson | Francis Granger | | Electoral vote | 8 | 0 | | Popular vote | 19,294 | 18,799 | | Percentage | 50.65% | 49.35% | |
 County Results | Van Buren 50–60% | Harrison 50-60% | |
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The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
Results
| 1836 United States presidential election in Connecticut[1] |
| Party | Candidate | Votes | Percentage | Electoral votes |
| | Democratic | Martin Van Buren | 19,294 | 50.65% | 8 |
| | Whig | William Henry Harrison | 18,799 | 49.35% | 0 |
| Totals | 38,093 | 100.0% | 8 |
See also
References
- ^ "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved August 4, 2012.
