1804 United States presidential election in Ohio
Election in Ohio
1808 → | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
The 1804 United States presidential election in Ohio took place as part of the 1804 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president. It was the first time that Ohio took part in United States presidential election.
Results
1804 United States presidential election in Ohio[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Thomas Jefferson (incumbent) | 2,593 | 87.69% | 3 | |
Federalist | Charles Cotesworth Pinckney | 364 | 12.31% | 0 | |
Totals | 2,957 | 100.0% | 3 |
References
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.
- v
- t
- e
articles
- Election timeline
results
- Connecticut
- Delaware
- Georgia
- Kentucky
- Maryland
- Massachusetts
- New Hampshire
- New Jersey
- New York
- North Carolina
- Ohio
- Pennsylvania
- Rhode Island
- South Carolina
- Tennessee
- Vermont
- Virginia
elections
This Ohio elections-related article is a stub. You can help Wikipedia by expanding it. |
- v
- t
- e